Python Nested Function Variable Assignment -

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this question has answer here:

i'm trying along following lines in python3:

i = 1337 def g():     print(i)     = 42 g()

but following error

unboundlocalerror: local variable 'i' referenced before assignment

i think understand error message means, why case? there way circumvent this?

in 2 words - when given variable name not assigned value within function references variable looked up. use global - , in such case python in global scope:

i = 1337  def g():     global     print     = 42  g()

you can read more on variable scopes in pep-0227


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