c - output of a function which has passByName parameter passing paradigm -

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• output of c code call reference [closed] 1 answer

i've tried figure out output of code .by way ,it not real question, kind of therical question, mean not original c code, kind of pl having c-code syntax , passed name parameter paradigm.

int x=12,y=10; void tswap(int pa, int pb) { int tmp; tmp=pa; pa=pb; pb=tmp; x=x+pa; x=x-pb; y++; printf("%d %d %d %d\n",pa,pb,x,y); }  int main() { int a=4; tswap(x,a); printf("%d %d %d\n",x,y,a); tswap(++x,++y); printf("%d %d %d\n",x,y,a); return 0; } 

i think output of first part should :

-4 12 -4 11 -4 11 12 

but find logical solution part tswap (++x, ++y) there can know how can handle part ?

thanks in advance !

tswap(++x,++y)  

is same as:

++x; ++y; tswap(x,y); 

making output:

4 12 4 11 4 11 4 12 5 12 13 12 13 4