Boost regex. Named group in two part -

i have problem boost::regex::regex_match. work turned on boost_regex_match_extra.

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what have:

(this simple example of problem, not real task)

string input1= "3 4 5"; string input2= "3 4 7"; 

what want get:

list output1= [3 4 5]; list output2= []; //not matched 

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regex:

(this working ok)

((?<group>[0-6])[ ]?)* 

output1: what["group"]=5 , what["group"].captures()= [3, 4, 5]

output2: not matched

the problem is:

i need collect data more one part of regex 1 group.

i tried:

((?<group>[0-6])[ ])*(?<group>[0-6]) 

output1: what["group"]=4 , what["group"].captures()=[3, 4]

output2: not matched

ok, understand. doesn't see second declaration of group.

i tried:

((?<group>[0-6])[ ])*(?&group) 

output1: what["group"]=4 , what["group"].captures()= [3, 4, 4]

output2: not matched

• but this? second 4 from? checks "group" pattern, because first example matches, second doesn't. doubles last found value instead of saving new. why? maybe forgot turn on flags?
• and there way in 1 group data different part of regex expression?

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i have more 1 group, token_iterator can't me.

and expression should configured in config file. static xpressive can't used.

this how interpret problem:

string: total price: $1,234

and want capture cost 1234 (without comma)

this isn't possible regex, there no way capture group , exclude parts in middle. being said, can use 2 match groups , lookaheads, , inside code stitch groups together. using above example, if don't know whether there comma or not (i.e. price ranges 1-5000) can

total price: \$(?p<price>\d{1,3})(?:(?=\,),(?p<price2>\d{3})|)

which matches 1-3 digits, comma, , if exists, use different name group , match second chunk.

here's nice resource regex testing: www.regex101.com