xml - How to get attribute values if they are not equal to some values? -


i have xml like:

<movies>     <movie name="aaa">         ...     </movie>     <movie name="bbb">         ...     </movie>     <movie name="ccc">         ...     </movie>     <movie name="ddd">         ...     </movie>     <movie name="eee">         ...     </movie> </movies> 

i name of movie if not 'aaa', or 'bbb', or 'ddd'. output be:

ccc eee 

because have several restrictions, don't think it's suitable use 'xsl:if'..i wrote xslt (i'm using xslt 1.0):

<xsl:value-of select="movies/movie/@name[not(self::aaa) , not(self::bbb) , not(self:ddd)]"/> 

but compiler complained there syntax error in sentence..and can't figure out why..

so me this? many thanks!!

try xpath expression:

movies/movie[@name!='aaa' , @name!='bbb' , @name!='ddd']/@name 

or one:

movies/movie/@name[.!='aaa' , .!='bbb' , .!='ddd'] 

the latter shorter, former can extended check other return not name, whole <movie> element - remove /@name @ end. or if want second, add /.. @ end.


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