How to tell C++ to use a different function (with the same name as another function)? -

i have 2 libraries included in program both have same function name, need able use both, need c++ know 1 i'm referring (in places referring 1 or other). reason why i'm doing because making own library , want have names functions, conflicting functions in else's library i've included, , make matters worse, of functions in library use functions in other persons library has same name.

my library .h/.cpp file way. also, when calling functions, don't want luggage such mynamespace::myfunc(). want call myfunc(). however, don't mind calling other persons function using namespace (though don't want modify library in case break something). (i'm new c++ btw)

heres new (test - far) code : not working w/ errors: error c2668: 'myfunc' : ambiguous call overloaded function

main program.cpp

    #include "otherslib.h"     #include "mylib.h"     #include <iostream>      using namespace mynamespace;      int main(){          std::cout << myfunc() << std::endl;          return 0;     } 

mylib.h

    #pragma once      namespace mynamespace{         int myfunc();     } 

mylib.cpp

    #include "mylib.h"      namespace mynamespace{         int myfunc(){             return 1;         }     } 

otherslib.h

    #pragma once      int myfunc(); 

otherslib.cpp

    #include "otherslib.h"      int myfunc(){         return 0;     } 

you should define functions in namespace, , use namespace when calling them.

namespace mynamespace {     int myfunc(etc) { ... } }  int main() {     cout << mynamespace::myfunc(); } 

to avoid having specify namespace time, this:

namespace mynamespace {     int myfunc(etc) { ... }      int main()      {         // call own myfunc:         myfunc();          // call myfunc:         ::myfunc();     } }